Who created Zed LOL?
Who created Zed LOL?
| Zed | |
|---|---|
| MR | 32 (+ 1.25) |
| Developer Info | |
| DDragon Key | Zed |
| Integer Key | 238 |
What is Zed W cooldown?
Living Shadow (W) Cooldown: 20/18.5/17/15.5/14. Cost: 40/35/30/25/20. Range: 650. Passive: Zed gains 30/35/40/45/50 Energy whenever he and his Shadows strike an enemy with the same Ability. Active: Zed\’s Shadow dashes forward, remaining in place for 5 seconds.
Who killed Zed LoL?
Ultimately, Kusho ordered Kayn to kill Zed to become the Master of Shadows, but in a relieving twist, the Shadow Reaper revealed that he will stay loyal to Zed after everything he has done for him, including taking him in when he was left to die by his own people.
Does Zed counter Shen?
Zed vs Shen Matchup Summary Zed has to counter Shen in 12.7% of his matches.
Who is Zed in the League of Legends?
Zed is a champion in League of Legends . For outdated and now non-canon lore entries, click here. Utterly ruthless and without mercy, Zed is the leader of the Order of Shadow, an organization he created with the intent of militarizing Ionia’s magical and martial traditions to drive out Noxian invaders.
Where did Zed find the Black Box League of Legends?
While Shen was growing to adopt his father’s dispassion, Zed refused to let lofty notions of balance stand in the way of punishing evil. He ventured deep into the temple’s hidden catacombs, and there he discovered an ornate, black box.
How did Zed get KAYN in League of Legends?
Zed took advantage of the ongoing war with Noxus, and the suffering it brought to the Ionian people. In the wake of a massacre near the Epool River, he came upon Kayn, a Noxian child soldier wielding nothing but a farmer’s sickle. Zed could see the boy was a weapon waiting to be sharpened, and took him as his personal student.
How long does Zed’s slash last in League of Legends?
Each enemy champion hit by Zed’s slash reduces Living Shadow’s cooldown by 2 seconds. Spell shield will only block one Shadow Slash even if two hit at the same time, the slow will not apply regardless.