Contributing

What is the max number for a triangle?

What is the max number for a triangle?

There is an infinite number unless there are angular or other restrictions. Consider that the smallest such triangle is the equilateral with sides 1/1/1 and perimeter 3.

What numbers can make a triangle?

This is the Triangular Number Sequence: 1, 3, 6, 10, 15, 21, 28, 36, 45.

What is the minimum perimeter of a triangle?

the MINIMUM perimeter of the triangle will be equal to the distance ece D’E + EF + ED” is shortest. The distance D’E + EF + ED” is shortest when there is a straight line connecting D’ to D” through points E and F.

How do you find the minimum area?

To find the minimum possible area, subtract the greatest possible error from each measurement, then multiply. The minimum possible area is 22.75 square miles.

When is the area of a triangle at its maximum?

Tap to check for your leaks. The area of a triangle is maximum when one of the three angles is 90° because then the height is maximum, otherwise it is maximum when all the three sides are equal or the triangle is equilateral triangle. The area of a triangle = 0.5 *base* height.

How do you find the area of a triangle?

area = 0.5 * b * h, where b is the length of the base of the triangle, and h is the height/altitude of the triangle. However, sometimes it’s hard to find the height of the triangle. In that cases, many other equations may be used, depending on what is known about the triangle:

How do you find the height of a triangle?

The best known and the simplest formula, which almost everybody remembers from school is: area = 0.5 * b * h, where b is the length of the base of the triangle, and h is the height/altitude of the triangle. However, sometimes it’s hard to find the height of the triangle.

How to calculate the area of an isosceles triangle?

Consider the diagram below: Let α be the base angle of an isosceles triangle ABC. Then half the apex angle at C equals 90° – α. Let O be the circumcenter of the triangle and D and E the midpoints of sides BC and AB, respectively. Thus, in the diagram, we successively obtain Area ( ΔABC) = AB×CE / 2 = R² (1 – cos (2α)) sin (2α).